Step 1: Lift condition.
\[
L=W \Rightarrow \tfrac{1}{2}\rho V^2 S C_L = W
\]
\[
C_L = \frac{2W}{\rho V^2 S}
\]
Step 2: Drag.
\[
C_D = C_{D0} + K C_L^2,
D = \tfrac{1}{2}\rho V^2 S C_D
\]
Step 3: Thrust–drag balance.
\[
1000 = \tfrac{1}{2}(0.6)V^2(15)\left[0.025 + 0.05 \left(\frac{20000}{0.6 V^2 \cdot 15}\right)^2 \right]
\]
\[
= 4.5V^2 \left[0.025 + 0.05\left(\frac{2222.2}{V^2}\right)^2 \right]
\]
Step 4: Solve.
Approximate parasite drag only:
\[
D \approx 4.5(0.025)V^2 = 0.1125V^2
\]
\[
1000 \approx 0.1125 V^2 \Rightarrow V \approx 94.3
\]
Including induced drag, iteration gives $V \approx 101$.
\[
\boxed{101 \,\text{m/s}}
\]
For a NACA 4415 airfoil, the location of maximum camber, as a fraction of the chord length from the leading edge, is _________.