Question

A galvanometer has a resistance of 50Ω. If a resistance of 12Ω is connected across its terminals, the total current flow through the galvanometer is:

• A. 3A
• B. 1A
• C. 2A
• D. 0.5A

Hint:

When resistors are connected in series, their total resistance is the sum of individual resistances.

Answer 1

The Correct Option is D

Step 1: Use Ohm's Law to calculate total current.
The total current can be calculated using Ohm's Law: \[ I = \frac{V}{R_{\text{total}}} \] The total resistance is the sum of the galvanometer resistance and the additional resistance, which gives: \[ R_{\text{total}} = 50 \, \Omega + 12 \, \Omega = 62 \, \Omega \]
Step 2: Conclusion.
Thus, the total current is: \[ I = \frac{V}{62 \, \Omega} = 0.5A \]