Question:

A galvanometer has a resistance of 50$\Omega$. If a resistance of 1$\Omega$ is connected across its terminals, the total current flow through the galvanometer is [$I_g$ represents the maximum current that can be passed through the galvanometer]

Updated On: Jan 18, 2023
  • 42$I_g$
  • 53$I_g$
  • 46$I_g$
  • 51$I_g$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is D

Solution and Explanation

In the galvanometer, $I_g$ = max. current through galvanometer, S = shunt resistance, G = galvanometer resistance then
$I_g(galvanometer)=1\bigg(\frac{S}{G+S}\bigg)$
$\Rightarrow I=I_g \bigg(\frac{G+S}{S}\bigg)=\bigg(\frac{50+1}{1}\bigg )I_g=51I_g$
Was this answer helpful?
0
0

Concepts Used:

Electric Current

Defining Electric Current

It is the rate of flow of electrons in a conductor. SI Unit - Ampere (A).

Electrons are negatively charged particles hence when they move a number of charges moves.

Note:- The ability of a particular substance to conduct electricity depends on the number of electrons that are able to move . Some of the materials allow current to flow better than others. 

What is an Electromotive Force?

If a force acts on electrons to make them move in a particular direction, then up to some extent random motion of the electrons will be eliminated. An overall movement in one direction. The force which acts on the electrons to move them in a certain direction is known as electromotive force and its quantity is known as voltage and is measured in V.