Step 1: Use the Fourier's Law for heat conduction.
The heat flow through a wall is given by Fourier's law:
\[
Q = \frac{k A (T_1 - T_2)}{L}
\]
Where:
- \( Q \) is the heat flow,
- \( k \) is the thermal conductivity (1 kJ/hr.m°C),
- \( A \) is the surface area (2 m²),
- \( T_1 \) and \( T_2 \) are the temperatures of the inner and outer surfaces (1000°C and 200°C),
- \( L \) is the thickness of the wall (1 m).
Step 2: Substitute the known values.
Substitute \( k = 1 \, \text{kJ/hr.m°C} \), \( A = 2 \, \text{m}^2 \), \( T_1 = 1000°C \), \( T_2 = 200°C \), and \( L = 1 \, \text{m} \) into the equation:
\[
Q = \frac{1 \times 2 \times (1000 - 200)}{1} = 2 \times 800 = 1600 \, \text{kJ/hr}
\]
Final Answer: \[ \boxed{2000} \]
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