The given function is f(x) = 2x - 5.
Therefore,
(i) f(0) = 2 x 0 - 5 = 0 - 5 = -5
(ii) f(7) = 2 x 7 - 5 = 14 - 5 = 9
(iii) f(-3) = 2 x (-3) - 5 = - 6 - 5 = -11
A relation R is defined in the set N as follows:
R = (x, y) : x = y - 3, y > 3
Then, which of the following is correct?
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is:
If the domain of the function $ f(x) = \log_7(1 - \log_4(x^2 - 9x + 18)) $ is $ (\alpha, \beta) \cup (\gamma, \delta) $, then $ \alpha + \beta + \gamma + \delta $ is equal to