Question

A flask contains a monoatomic and a diatomic gas in the ratio of \( 4:1 \) by mass at a temperature of \( 300K \). The ratio of average kinetic energy per molecule of the two gases is:

• A. \( 1:1 \)
• B. \( 2:1 \)
• C. \( 4:1 \)
• D. \( 1:4 \)

Hint:

For an ideal gas:
- The average kinetic energy depends only on temperature.
- It is independent of molecular mass or type of gas.
- \( KE = \frac{3}{2} k_B T \) for all gases.

Answer 1

The Correct Option is A

Step 1: The average kinetic energy per molecule of a gas is given by:
\[ KE = \frac{3}{2} k_B T \]
Step 2: Since temperature \( T \) is the same for both gases, the kinetic energy per molecule remains equal. Hence, the ratio is:
\[ 1:1 \]