Question:

A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is (give answer in two decimal places).

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The net slip on a fault can be calculated using the horizontal slip and the pitch of the lineation.
Updated On: Nov 18, 2025
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Solution and Explanation

Step 1: Understanding the question.
The question asks for the net slip on a fault based on the given pitch and horizontal slip values.
Step 2: Analyzing the solution.
The formula for net slip on a fault is given by: \[ \text{Net Slip} = \text{Horizontal Slip} \times \sin(\text{Pitch}) \] Substitute the values: \[ \text{Net Slip} = 1.25 \times \sin(30^\circ) = 1.25 \times 0.5 = 0.64 \, \text{m} \] Step 3: Conclusion.
The correct answer is 0.64 m, which is the net slip on the fault.
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