Series of discounts of\(10\%, 20\% and 40\%\)
Let the original number be 100.
After applying a series of discount
\(100(1-10\%) (1-20\%)(1-40\%)\)
\(\frac{90}{100}\times\frac{80}{100}\times\frac{60}{100}\times100\)
\(43.2\%\)
The required discount =\(100-43.2\)
Discount =\(56.80%\)
\(56.80\%\)is a single discount of this series.
The correct answer is (B):\(56.80\%\)
An electricity utility company charges ₹7 per kWh. If a 40-watt desk light is left on for 10 hours each night for 180 days, what would be the cost of energy consumption? If the desk light is on for 2 more hours each night for the 180 days, what would be the percentage-increase in the cost of energy consumption?