Question:

A deuteron contains a proton and a neutron and has a mass of 2.013553 u. Calculate the mass defect for it in u and its energy equivalence in MeV.
Given:
mp=1.007277 m_p = 1.007277 u, mn=1.008665 m_n = 1.008665 u, 1 1 u = 931.5 931.5 MeV/c2 c^2 .

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Mass defect arises due to the conversion of missing mass into energy, which holds the nucleus together. This is why nuclear reactions release enormous energy.
Updated On: Feb 26, 2025
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Solution and Explanation

Step 1: Calculate the Mass Defect Mass defect is given by: Δm=(mp+mn)mdeuteron \Delta m = (m_p + m_n) - m_{\text{deuteron}} Substituting values: Δm=(1.007277+1.008665)2.013553 \Delta m = (1.007277 + 1.008665) - 2.013553 Δm=2.0159422.013553 \Delta m = 2.015942 - 2.013553 Δm=0.002389 u \Delta m = 0.002389 \text{ u}

Step 2: Calculate the Binding Energy Binding energy is given by: Eb=Δm×931.5 MeV E_b = \Delta m \times 931.5 \text{ MeV} Substituting Δm=0.002389 \Delta m = 0.002389 u: Eb=0.002389×931.5 E_b = 0.002389 \times 931.5 Eb2.224 MeV E_b \approx 2.224 \text{ MeV} Thus, the mass defect is 0.002389 0.002389 u, and the binding energy is 2.224 2.224 MeV.
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