Assume the quantity bought by him be 12x,15x and 20x.
The Selling Price of the first two be a, b and that of third one be c.
a + b = 120% of (100 × 12x + 80 × 15x)
a + b = 2880x
a + b + c = 100 × 12x + 80 × 15x + 60 × 20x = 3600x
c = 3600x - 2880x
c = 720x
and CP = 20x × 60 = 1200x (Here CP is Cost Price)
Loss Percentage = \(\frac{CP-SP}{CP}×100\) (Here CP is Cost Price and SP is Selling Price)
Loss Percentage = 1200X-720X/1200X = 480/1200
Loss Percentage = 40%
The correct option is (A)