Question

A current of 2 A is flowing in the sides of an equilateral triangle of side 9 cm. The magnetic field at the centroid of the triangle is

• A. \( 1.66 \times 10^{-5} \, \text{T} \)
• B. \( 1.22 \times 10^{-5} \, \text{T} \)
• C. \( 1.33 \times 10^{-5} \, \text{T} \)
• D. \( 1.44 \times 10^{-4} \, \text{T} \)

Hint:

To find the magnetic field at the centroid of a current-carrying triangle, use the Biot-Savart law or Ampere's circuital law.

Answer 1

The Correct Option is A

The magnetic field at the centroid of a current-carrying triangle is determined using Ampere's law and Biot-Savart law. The current in the sides of the triangle produces a magnetic field at the centroid, which is \( 1.66 \times 10^{-5} \, \text{T} \).