The correct option is (A): 20790
Explanation: There are 6 bowlers, 3 wicket keepers and 11 batsman in all. The number of ways in which a team of 4 bowlers, 2 wicket keepers and 5 batsman can be chosen
=\(C_4^6\times C_2^3\times C\binom{11}{5}\)
=\(\frac{6\times5}{2\times1}\times\frac{3\times2}{2\times1}\times\frac{11\times10\times9\times8\times7}{5\times4\times3\times2\times1}\)
\(=15 × 3 × 462 = 20790\)