A copper wire of length 10 m and radius \((\frac{10^{-2}} { √π})\) has electrical resistance of 10 Ω. The current density in the wire for an electric field strength of \((\frac{V}{m})\) is:
- 104 \(\frac{A}{m^2}\)
- 106 \(\frac{A}{m^2}\)
- 10-5 \(\frac{A}{m^2}\)
- 105 \(\frac{A}{m^2}\)
The Correct Option is D
Solution and Explanation
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Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).