Question

A coordination complex compound of cobalt has the molecular formula containing five ammonia molecules, one nitro group and two chlorine atoms for one cobalt atom. One mole of this compound produces three mole ions in an aqueous solution; on reacting with excess of \( \text{AgNO}_3 \), \( \text{AgCl} \) is precipitated. The ionic formula for this complex would be:

• A. \( [\text{Co}(\text{NH}_3)_5(\text{NO}_3)] \text{Cl}_2 \)
• B. \( [\text{Co}(\text{NH}_3)_5(\text{Cl})] (\text{Cl}_2) \)
• C. \( [\text{Co}(\text{NH}_3)_4(\text{NO}_3)_2] \)
• D. \( [\text{Co}(\text{NH}_3)_5] (\text{NO}_3)_2 \)

Hint:

In coordination compounds, the number of ligands and counterions is crucial in determining the ionic formula.

Answer 1

The Correct Option is A

The coordination compound with five ammonia molecules, one nitro group, and two chlorine ions gives the ionic formula \( [\text{Co}(\text{NH}_3)_5(\text{NO}_3)] \text{Cl}_2 \), which dissociates in water to give three ions.
Final Answer: \[ \boxed{[\text{Co}(\text{NH}_3)_5(\text{NO}_3)] \text{Cl}_2} \]