Question

A conducting circular loop of radius \( r \) carries a constant current \( i \). It is placed in a uniform magnetic field \( \vec{B} \) such that \( \vec{B} \) is perpendicular to the plane of the loop. The magnetic force acting on the loop is

• A. \( irB_0 \)
• B. \( 2\pi irB_0 \)
• C. zero
• D. \( irB_0 \)

Hint:

For a conducting loop in a uniform magnetic field, the force acting on the loop is given by \( F = i r B_0 \), where \( i \) is the current, \( r \) is the radius, and \( B_0 \) is the magnetic field strength.

Answer 1

The Correct Option is A

Step 1: Use the formula for the magnetic force on a current-carrying loop.
The force on a current-carrying loop in a magnetic field is given by: \[ F = i r B_0 \] where \( i \) is the current, \( r \) is the radius of the loop, and \( B_0 \) is the magnetic field.
Step 2: Conclusion.
Thus, the magnetic force acting on the conducting circular loop is \( irB_0 \).
Final Answer: \[ \boxed{irB_0} \]