1. Identify the Key Properties of P
P is described as:
- Colorless
- Neutral
- Paramagnetic
- Oxide of Nitrogen
2. Evaluate Possible Nitrogen Oxides Based on the Properties of P
- $N_2O$: Colorless, neutral, diamagnetic.
- $NO$: Colorless, neutral, paramagnetic.
- $NO_2$: Reddish brown, acidic, paramagnetic.
- $N_2O_4$: Colorless, acidic, diamagnetic.
- $N_2O_5$: Colorless solid, acidic, diamagnetic.
- $N_2O_3$: Blue solid, acidic, diamagnetic.
Based on these properties, P must be $NO$.
3. Determine the Identity of Q
Q is formed by oxidation of P ($NO$) and is a reddish-brown gas. $NO$, when oxidized, forms $NO_2$, which is a reddish-brown gas:
$$
2NO + O_2 \rightarrow 2NO_2
$$
Therefore, Q is $NO_2$.
4. Determine the Identity of R
Q ($NO_2$) on cooling gives a colorless gas R. $NO_2$ dimerizes at low temperatures to form $N_2O_4$, which is colorless.
$$
2NO_2 \rightleftharpoons N_2O_4
$$
Therefore, R is $N_2O_4$.
5. Determine the Identity of S
R ($N_2O_4$) on reaction with P ($NO$) gives a blue solid S. $NO$ reacts with $N_2O_4$ to give $N_2O_3$, which is a blue solid.
$$
NO + N_2O_4 \rightarrow N_2O_3
$$
Therefore, S is $N_2O_3$.
6. Summarize the Identities of P, Q, R, and S
- P = $NO$
- Q = $NO_2$
- R = $N_2O_4$
- S = $N_2O_3$
7. Compare with the Given Options
The set of compounds matches option (C).
Final Answer:
(C) $NO$ $NO_2$ $N_2O_4$ $N_2O_3$
The paramagnetic oxide of nitrogen P is nitric oxide (NO). Upon oxidation, NO reacts with oxygen to form nitrogen dioxide (NO2), which is a reddish-brown gas (Q).
So, the correct answer is (C) : NO NO2 N2O4 N2O3.