Question:
A coil of wire of certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a second similar coil of 500 turns will be
A coil of wire of certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a second similar coil of 500 turns will be
Updated On: Jul 5, 2022
- 74 mH
- 75 mH
- 76 mH
- 77 mH
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The Correct Option is B
Solution and Explanation
Inductance, L $\propto$ N$^2$
$\therefore$ Inductance of similar coil of different turns is given by L' = L $\frac{N'^2}{N^2} = 108 \times \left( \frac{500}{6000} \right)^2 $ = 75 m H
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter