Question:

A coil of wire of certain radius has 600 turns and a self inductance of 108 mH. The self inductance of a second similar coil of 500 turns will be

Updated On: Jul 5, 2022

74 mH
75 mH
76 mH
77 mH

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The Correct Option is B

Solution and Explanation

Inductance, L

\propto

^2

\therefore

Inductance of similar coil of different turns is given by L' = L

\frac{N'^2}{N^2} = 108 \times \left( \frac{500}{6000} \right)^2

= 75 m H

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Notes on Electromagnetic induction

Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

When we place the conductor in a changing magnetic field.
When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

e = induced voltage
N = number of turns in the coil
Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
t = time

Applications of Electromagnetic Induction

Electromagnetic induction in AC generator
Electrical Transformers
Magnetic Flow Meter