Question:

A coil of mean area $500\, cm^{2}$ and having $1000$ turns is held perpendicular to a uniform field of $0.4$ gauss The coil is turned through $180^{\circ}$ in $\frac{1}{10}$ second. The average induced emf is

Updated On: Jul 5, 2022
  • $0.02\, V$
  • $0.04\, V$
  • $1.4\, V$
  • $0.08\, V$
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The Correct Option is B

Solution and Explanation

Here, $A=500\, cm^{2} = 500 \times 10^{-4}\, m^{2}$ $N=1000, B=0.4\,G=0.4 \times 10^{-4}\,T$ $t=\frac{1}{10}\,s$ When the coil is held perpendicular to the field, the normal to the plane of the coil makes an angle of $0^{\circ}$ with the field $B$. $\therefore$ initial flux, $\phi_{1}=BA\, cos\, 0^{\circ}=BA$ final flux, $\phi_{2}=BA\, cos\, 180^{\circ}=-BA$ $\varepsilon =-N (\frac{(\phi_{2}-\phi_{1})}{t})=-N (\frac{-BA-BA}{t})$ $=\frac{2NBA}{t}$ $=\frac{ 2\times1000\times0.4\times10^-4\times500\times10^{-4} }{ 1/10}$ $=0.04 \, V$
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Concepts Used:

Electromagnetic Induction

Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-

  1. When we place the conductor in a changing magnetic field.
  2. When the conductor constantly moves in a stationary field.

Formula:

The electromagnetic induction is mathematically represented as:-

e=N × d∅.dt

Where

  • e = induced voltage
  • N = number of turns in the coil
  • Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
  • t = time

Applications of Electromagnetic Induction

  1. Electromagnetic induction in AC generator
  2. Electrical Transformers
  3. Magnetic Flow Meter