Question:
A coil having a resistance of 20 ohm and inductance 20 henry is connected to 120 V battery. Find the value of energy stored in the magnetic field when the steady state is reached
A coil having a resistance of 20 ohm and inductance 20 henry is connected to 120 V battery. Find the value of energy stored in the magnetic field when the steady state is reached
Updated On: Jul 5, 2022
- 250 J
- 150 J
- 300 J
- 360 J
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The Correct Option is D
Solution and Explanation
Here, R = 20$\Omega$, L = 20 H and E = 120 V
$\therefore$ $I_0 = \frac{E}{R} = \frac{120}{20}$ = 6A
Energy stored = $\frac{1}{2} LI_0\, ^2 = \frac{1}{2} \times 20 \times 36$ = 360 J
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter