The two boys in corner can be arranged in =\(2! \) ways
Now, the remaining boys can be arranged in =\(18!\) ways
There are 6 girls who can be arranged in=\(6!\) ways
Therefore, Total number of ways in which all the students can be arranged
\( = 2! ×18!×6!\)
\(=18! ×1440\)
The correct answer is (A) :18! x 1440