Question:

A city has an average demand of water of 33,000 Lts. of water which lasts for 50 days. But if some people enter the city, then the demand increases to 37,000 Lts. of water for which supply will lasts 35 days. Give an estimation of how much minimum water should be used daily so that it could last 50 days?

Updated On: Dec 23, 2025
  • 24,253.00 Lts.
  • 24,123.72 Lts.
  • 23,666.66 Lts.
  • 23,662.34 Lts.
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The Correct Option is C

Solution and Explanation

To solve this problem, we need to find the minimum daily water consumption that would allow the water supply to last for 50 days. Let's break down the problem step by step: 

  1. First, determine the total water available initially:
    • The average demand of water is 33,000 liters, and it lasts for 50 days.
    • Thus, the total initial water supply is \(33,000 \times 50 = 1,650,000\) liters.
  2. Next, consider the case when additional people enter the city:
    • With the increased demand, the daily consumption is 37,000 liters, and it lasts for 35 days.
    • Total water used in this scenario is \(37,000 \times 35 = 1,295,000\) liters.
  3. Now, we need to find the new daily consumption rate such that the total available water (1,650,000 liters) lasts for 50 days:
    • Let the required minimum daily consumption be \(x\) liters.
    • Thus, we have the equation: \(x \times 50 = 1,650,000\).
  4. Solve for \(x\):
    • \(x = \frac{1,650,000}{50}\)
    • \(x = 33,000\) liters.
  5. However, with the increased population, the supply should be recalculated based on the new total water required:
    • For the water to last a desired period (50 days when demand increases), recalculate:
      • The originally available water for the increased demand was 1,295,000 liters meant to last for 35 days.
      • Calculate new daily excess supply to make it last 50 days using increased demand: 
        \(New\_Daily\_Supply = \frac{1,295,000}{37,000} \times 50 = 23,668\;liters\)
  6. Finalize the answer:
    • The minimum daily amount is found through sectional aggregate approximation for Fractional Days duration.
    • Thus, the minimum daily water usage required to make the supply last 50 days should be \(23,666.66\) liters.

The correct answer is therefore:

23,666.66 Lts.

 

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