The correct option is (C): 5.28 minutes
Relative speed =\(3.75+4.5=8.25\space km/hr=8.25\times \frac{5}{18}\)\(=\frac{13.75}{6} \space m/s\)
The time taken for them to meet for the first time=\(\frac{distance}{speed}\)\(=\frac{726}{\frac{13.75}{6}}\)=\(\frac{726\times6}{13.75}\)=\(316.8 \space sec\)
\(⇒\)\(\frac{316.8}{60}=5.28\space minutes\)