Question:

A circular coil of $300$ turns and diameter $14\, cm$ carries a current of $15 \,A$. The magnitude of magnetic moment associated with the loop is

Updated On: Jun 23, 2023
  • $51.7\, J\, T^{-1}$
  • $69.2\, J\, T^{-1}$
  • $38.6\, J\, T^{-1}$
  • $19.5\, J\, T^{-1}$
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The Correct Option is B

Solution and Explanation

Here, $N = 300$, $I = 15 \,A$, $r = 7 \,cm = 7 \times 10^{-2} \,m$ $\therefore\quad M = NIA = NI \times \pi r^{2}$ $= 300 \times 15 \times 3.14 \times \left(7 \times 10^{-2}\right)^{2} = 69.2\, J \,T^{-1}$
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Notes on Magnetism and matter

Concepts Used:

Magnetism & Matter

Magnets are used in many devices like electric bells, telephones, radio, loudspeakers, motors, fans, screwdrivers, lifting heavy iron loads, super-fast trains, especially in foreign countries, refrigerators, etc.

Magnetite is the world’s first magnet. This is also called a natural magnet.  Though magnets occur naturally, we can also impart magnetic properties to a substance. It would be an artificial magnet in that case.

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Some of the properties of the magnetic field lines are:

  • The lines and continuous and outside the magnet, the field lines originate from the North pole and terminate at the South pole
  • They form closed loops traversing inside the magnet. 
  • But here the lines seem to originate from the South pole and terminate at the North pole to form closed loops.
  • More number of close lines indicate a stronger magnetic field
  • The lines do not intersect each other
  • The tangent drawn at the field line gives the direction of the field at that point.