Question:
A charged particle \(q\) is shot with speed \(v\) towards another fixed charged particle \(Q\). It approaches \(Q\) upto a closest distance r and then returns. If \(q\) were given a speed \(2v\), the closest distance of approach would be
A charged particle \(q\) is shot with speed \(v\) towards another fixed charged particle \(Q\). It approaches \(Q\) upto a closest distance r and then returns. If \(q\) were given a speed \(2v\), the closest distance of approach would be
Updated On: Jun 21, 2024
- \(r\)
- \(2r\)
- \(\frac r2\)
- \(\frac r4\)
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The Correct Option is D
Solution and Explanation
The correct option is (D): \(\frac r4\).
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