Question:

A charge \( q \) is moving with a velocity \( v \) parallel to a magnetic field \( B \). Force on the charge due to magnetic field is

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The force on a moving charge in a magnetic field is given by \( F = qvB \sin \theta \).
Updated On: Jan 14, 2026
  • \( qvB \)
  • \( \frac{qB}{v} \)
  • zero
  • \( Bv/q \)
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The Correct Option is A

Solution and Explanation


Step 1: Understanding the force.
The force acting on a charged particle moving in a magnetic field is given by the equation \( F = qvB \sin \theta \), where \( \theta \) is the angle between the velocity and magnetic field. For \( \theta = 90^\circ \), this simplifies to \( F = qvB \).

Step 2: Conclusion.
The force on the charge is \( qvB \).
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