Question:
A capacitor of $5\,\mu\,F$ is charged to a potential difference of 200V. If it is discharged through two resistors of 700 and 300 ohms, what is the energy dissipated in each of the two resistors ?
A capacitor of $5\,\mu\,F$ is charged to a potential difference of 200V. If it is discharged through two resistors of 700 and 300 ohms, what is the energy dissipated in each of the two resistors ?
Updated On: Jul 5, 2022
- 0.07 J, 0.03 J
- 0.03 J,0.07 J
- 0.7 J, 0.3 J
- 0.3 J,0.7 J
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The Correct Option is A
Solution and Explanation
Current in the circuit is given by : $l^2$ [700+300] = $\frac{1}{2} \times 5 \times 10^{-6} \times (200)^2$
This gives ; $l^2 = 0.1 \times 10^{-3}$
Hence $H_1 = l^2\, R_1$ = 0.07 J
And $H_2 = I^2R_2$ = 0.03 J
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Concepts Used:
Electromagnetic Induction
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
- When we place the conductor in a changing magnetic field.
- When the conductor constantly moves in a stationary field.
Formula:
The electromagnetic induction is mathematically represented as:-
e=N × d∅.dt
Where
- e = induced voltage
- N = number of turns in the coil
- Φ = Magnetic flux (This is the amount of magnetic field present on the surface)
- t = time
Applications of Electromagnetic Induction
- Electromagnetic induction in AC generator
- Electrical Transformers
- Magnetic Flow Meter