Question:

A can do a piece of work in 6 days while B alone can do it in 8 days. With the help of C, they can complete the work in 2 days. If they are paid Rupees 720 for the whole work, how much money A gets?

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In work and wages problems, always reduce the data to "1-day work" (or unit work). Then compare each person's contribution over the total period and divide wages in the same ratio.

Updated On: Dec 9, 2025
  • Rupees 180
  • Rupees 240
  • Rupees 300
  • Rupees 420
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The Correct Option is B

Solution and Explanation

Step 1: Work rates of A and B 
A completes the work in 6 days. Hence, A's 1-day work = \( \frac{1}{6} \). 
B completes the work in 8 days. Hence, B's 1-day work = \( \frac{1}{8} \). 
Step 2: Combined rate of A, B, and C 
Together, A, B, and C complete the work in 2 days. Hence, their combined 1-day work = \( \frac{1}{2} \). 
Step 3: Finding C's rate 
\[ \frac{1}{6} + \frac{1}{8} + \text{C's 1-day work} = \frac{1}{2} \] 
Take LCM of 6 and 8, which is 24: 
\[ \frac{4}{24} + \frac{3}{24} + \text{C's 1-day work} = \frac{1}{2} \] 
\[ \frac{7}{24} + \text{C's 1-day work} = \frac{1}{2} \] 
\[ \text{C's 1-day work} = \frac{1}{2} - \frac{7}{24} = \frac{12}{24} - \frac{7}{24} = \frac{5}{24} \] 
Step 4: Work done individually in 2 days 
- Work done by A in 2 days = \( 2 \times \frac{1}{6} = \frac{2}{6} = \frac{1}{3} \). 
- Work done by B in 2 days = \( 2 \times \frac{1}{8} = \frac{2}{8} = \frac{1}{4} \). 
- Work done by C in 2 days = \( 2 \times \frac{5}{24} = \frac{10}{24} = \frac{5}{12} \). 
Check: \(\frac{1}{3} + \frac{1}{4} + \frac{5}{12} = \frac{4}{12} + \frac{3}{12} + \frac{5}{12} = 1 \). ✅ 
Step 5: Payment distribution 
The total payment is distributed in the ratio of work done. 
Work fractions = A : B : C = \( \frac{1}{3} : \frac{1}{4} : \frac{5}{12} \). 
Take LCM of 12: \( \frac{4}{12} : \frac{3}{12} : \frac{5}{12} = 4 : 3 : 5 \). 
Step 6: A's share 
Total ratio sum = \( 4 + 3 + 5 = 12 \). 
A's share = \( \frac{4}{12} \times 720 = \frac{1}{3} \times 720 = 240 \). ✅ 
\[ \boxed{240} \]

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