Question

A bulb draws a current of 0-2 A from a 220 V source. The resistance of the filament of the bulb is

• A. 1100 Ω
• B. 110 Ω
• C. 44 Ω
• D. 222 Ω

Answer 1

The Correct Option is A

Step 1: Use Ohm's Law to relate voltage, current, and resistance.

Ohm's Law states:

\[ V = I \cdot R, \]

where \( V \) is the voltage, \( I \) is the current, and \( R \) is the resistance. Rearranging for \( R \):

\[ R = \frac{V}{I}. \]

Step 2: Substitute the given values.

Substitute \( V = 220 \, \text{V} \) and \( I = 0.2 \, \text{A} \):

\[ R = \frac{220}{0.2} = 1100 \, \Omega. \]

Final Answer: The resistance of the filament is \( \mathbf{1100 \, \Omega} \), which corresponds to option \( \mathbf{(1)} \).