Question:

A body of mass 60 g experiences a gravitational force of 3.0 N, when placed at a particular point. The magnitude of the gravitational field intensity at that point is:

Updated On: May 3, 2025
  • 0.05 N/kg
  • 50 N/kg
  • 20 N/kg
  • 180 N/kg
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The Correct Option is B

Solution and Explanation

To determine the gravitational field intensity at the point where a body of mass 60 g experiences a gravitational force of 3.0 N, we should use the formula for gravitational field intensity \(E\), which is given by:
\[E = \frac{F}{m}\]
Where:
  • F is the gravitational force experienced by the body, which is 3.0 N.
  • m is the mass of the body. Here, the mass is given in grams, so we need to convert it to kilograms. Since 1 kg = 1000 g, the mass is \(60 \, \text{g} = 0.06 \, \text{kg}\).
Substituting the values into the formula, we get:
\[E = \frac{3.0 \, \text{N}}{0.06 \, \text{kg}} = 50 \, \text{N/kg}\]
Therefore, the magnitude of the gravitational field intensity at that point is 50 N/kg.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].