Question:

A body of mass $ 1.5 \, \text{kg} $ is dropped from a height of $ 20 \, \text{m} $. What is its speed just before hitting the ground? (Assume $ g = 9.8 \, \text{m/s}^2 $)

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Remember: When an object is dropped from a height, its initial velocity is zero, and its final velocity depends only on the height and gravity.
Updated On: Apr 22, 2025
  • \( 19.8 \, \text{m/s} \)
  • \( 14 \, \text{m/s} \)
  • \( 20 \, \text{m/s} \)
  • \( 9.8 \, \text{m/s} \)
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The Correct Option is A

Solution and Explanation

Step 1: Use the equation for final velocity in free fall
For an object dropped from a height, the final velocity \( v \) just before hitting the ground can be calculated using the equation: \[ v = \sqrt{2gh} \] where: - \( g \) is the acceleration due to gravity, - \( h \) is the height from which the object is dropped.
Step 2: Substitute the given values
Given: - \( g = 9.8 \, \text{m/s}^2 \) - \( h = 20 \, \text{m} \) \[ v = \sqrt{2 \times 9.8 \times 20} = \sqrt{392} \approx 19.8 \, \text{m/s} \]
Answer:
Therefore, the speed of the body just before hitting the ground is \( 19.8 \, \text{m/s} \). So, the correct answer is option (1).
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