Step 1: Use the equation for final velocity in free fall
For an object dropped from a height, the final velocity \( v \) just before hitting the ground can be calculated using the equation:
\[
v = \sqrt{2gh}
\]
where:
- \( g \) is the acceleration due to gravity,
- \( h \) is the height from which the object is dropped.
Step 2: Substitute the given values
Given:
- \( g = 9.8 \, \text{m/s}^2 \)
- \( h = 20 \, \text{m} \)
\[
v = \sqrt{2 \times 9.8 \times 20} = \sqrt{392} \approx 19.8 \, \text{m/s}
\]
Answer:
Therefore, the speed of the body just before hitting the ground is \( 19.8 \, \text{m/s} \). So, the correct answer is option (1).