Question:

A body of 2 kg mass slides down with an acceleration of \( 4 \, \text{ms}^{-2} \) on an inclined plane having a slope of \( 30^\circ \). The external force required to take the same body up the plane with the same acceleration will be (Acceleration due to gravity \( g = 10 \, \text{ms}^{-2} \))

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While moving up the plane, the external force must overcome both gravity and friction, along with providing the necessary acceleration. Use Newton’s second law along the incline for calculations.
Updated On: Mar 24, 2025
  • \( 8 \, \text{N} \)
  • \( 16 \, \text{N} \)
  • \( 22 \, \text{N} \)
  • \( 20 \, \text{N} \)
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The Correct Option is D

Solution and Explanation


Step 1: Understanding the Given Data
- Mass of the body: \( m = 2 \, \text{kg} \)
- Acceleration while sliding down: \( a = 4 \, \text{ms}^{-2} \)
- Inclination angle: \( \theta = 30^\circ \)
- Acceleration due to gravity: \( g = 10 \, \text{ms}^{-2} \)
Step 2: Finding the Net Force while Sliding Down
The equation of motion along the incline while sliding down is: \[ mg \sin\theta - F_{\text{friction}} = ma \] \[ (2 \times 10) \sin 30^\circ - F_{\text{friction}} = 2 \times 4 \] \[ 10 - F_{\text{friction}} = 8 \] \[ F_{\text{friction}} = 2 \, \text{N} \] Step 3: Finding the Required Force to Move Up
For moving up with the same acceleration: \[ F_{\text{external}} - mg \sin\theta - F_{\text{friction}} = ma \] \[ F_{\text{external}} - 10 - 2 = 8 \] \[ F_{\text{external}} = 20 \, \text{N} \] Step 4: Conclusion
Thus, the external force required to take the body up with the same acceleration is: \[ \mathbf{20 \, \text{N}}. \]
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