Question

A body moving with uniform acceleration travels a distance of 25 m in the fourth second and 37 m in the sixth second. The distance covered by the body in the next two seconds is

• A. 63 m
• B. 84 m
• C. 49 m
• D. 92 m \bigskip

Hint:

we can find the acceleration and then use it to find the distance covered in the next two seconds.

Answer 1

The Correct Option is D

We can use the formula for the distance traveled by a body in the \(n\)-th second: \[ S_n = u + \frac{a}{2}(2n - 1), \] where \( u \) is the initial velocity, \( a \) is the acceleration, and \( n \) is the second. From the given information, the distance covered in the fourth second is 25 m and in the sixth second is 37 m. Using these two equations, we can find the acceleration and then use it to find the distance covered in the next two seconds. After solving for acceleration \( a \) and using the formula, the distance covered in the next two seconds is 92 m.