Question

A body is projected with velocity 20 m/s at an angle of \(30^\circ\) to the horizontal. The maximum height reached by the body is (\(g = 10\ \text{m/s}^2\)):

• A. 5 m
• B. 10 m
• C. 15 m
• D. 20 m

Hint:

Maximum height depends only on vertical velocity component.

Answer 1

The Correct Option is B

Step 1: Vertical component of velocity \[ u_y = 20\sin30^\circ = 10\ \text{m/s} \] Step 2: Maximum height, \[ H = \frac{u_y^2}{2g} = \frac{10^2}{2\times10} = 5\ \text{m} \]