Let the speed of the boat in still water be \( b \) km/h and the speed of the stream be \( s \) km/h.
The time taken for the boat to go upstream is given by:
\[
\text{Time} = \frac{\text{Distance}}{\text{Speed}} = \frac{0.75}{b - s} \quad \text{hours}.
\]
The time taken for the boat to go downstream is:
\[
\text{Time} = \frac{0.75}{b + s} \quad \text{hours}.
\]
We are given that the time for upstream is 11 minutes 15 seconds, which is \( \frac{11.25}{60} \) hours, and the time for downstream is 7 minutes 30 seconds, which is \( \frac{7.5}{60} \) hours.
Thus, we have the system of equations:
\[
\frac{0.75}{b - s} = \frac{11.25}{60}, \quad \frac{0.75}{b + s} = \frac{7.5}{60}.
\]
Solving these equations, we get the value of \( b = 5 \) km/h.
Therefore, the speed of the boat in still water is 5 km/h, which corresponds to option (4).