Question:

A block of mass 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force of 2.5 N is applied on the block as shown in the figure, the frictional force between the block and the floor will be

Updated On: Jul 12, 2022
  • 2.5 N
  • 5 N
  • 7.84 N
  • 10 N
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Given: $\mu=0.4 \quad F =2.5 N$ $m =2 kg$ $N = mg =20 N$ The max value of friction $=\mu N =0.4 \times 20=8 N$ Since, the force applied is $2.5 N$ there is no need for friction to attain its max. value. $\therefore$ Frictional force $=2.5 N$
Was this answer helpful?
0
0

Concepts Used:

Laws of Motion

The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.

Newton’s First Law of Motion

Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion

Newton's 2nd law of motion deals with the relation between force and acceleration. According to the second law of motion, the acceleration of an object as built by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Newton’s Third Law of Motion

Newton's 3rd law of motion states when a body applies a force on another body that there is an equal and opposite reaction for every action.