Question:

A black powder when heated with cone. $HCl$ gives a greenish yellow gas. The gas acts as an oxidising and a bleaching agent. When it is passed over slaked lime, a white powder is formed which is a ready source of gas. The black powder and white powder respectively are

Updated On: Jul 5, 2022

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The Correct Option is B

\underset{\text{Black powder}}{ {MnO2}}+

\underset{\text{(conc.)}}{ {4HCl}}

{-> MnCl2 +2H2O +}

\underset{\text{Greenish yellow gas}}{ {Cl2}}

{Cl2 +H2O \to 2HCl +[O]}

Coloured matter

{+[O] ->}

Colourless matter

\underset{\text{Slaked lime}}{ {2Ca(OH)2}}+ {2Cl2 ->}

$\underset{\text{Bleaching powder (white)}}{ {Ca(OCl)2}}+

{CaCl2 +2H2O}$

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P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.