Question:

A black hole is an object whose gravitational field is so strong that even light cannot escape from it. To what approximate radius would earth (mass $= 5.98 \times 10^{24} \, kg$) have to be compressed to be a black hole?

Updated On: May 5, 2024
  • $10^{-9} \, m$
  • $10^{-6} \, m$
  • $10^{-2} \, m$
  • $100\, m$
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The Correct Option is C

Solution and Explanation

Light cannot escape from a black hole,
$v_{esc} = c$
$\sqrt \frac {2GM}{R} = c$ or $R = \frac {2GM}{c^2}$
$R = \frac {2\, \times \,6.67 \times 10^{-11}\,N \,m^2\, kg^{-2}\, \times \,5.98\, \times \,10^{24}\,kg}{(3 \,\times \,10^8 \,ms^{-1})^2}$
$ = 8.86 \times 10^{-3} \,m \approx 10 ^{-2}\, m $
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].