Question:

A balloon with mass m is descending down with an acceleration a (where a < g). How much mass should be removed from it so that it starts moving up with an acceleration $a$?

Updated On: May 21, 2024
  • $\frac{2ma}{g+a}$
  • $\frac{2ma}{g-a}$
  • $\frac{ma}{g+a}$
  • $\frac{ma}{g-a}$
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The Correct Option is A

Solution and Explanation

Let F be the upthrust of the air. As the balloon is descending down with an acceleration a,
$\therefore mg=F=ma$ ... (i)

Let mass $m_0$ be removed from the balloon so that it starts moving up with an acceleration a. Then,
$F-(m-m_0)g=(m-m_0)a$
$F-mg+m_0g=ma-m_0a$ ... (ii)
Adding eqn. (i) and eqn. (ii), we get
$m_0g=2ma-m_0a$
$m_0g+m_0a=2ma$
$m_0(g+a)=2ma$
$m_0=\frac{2ma}{a+g}$
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Concepts Used:

Laws of Motion

The laws of motion, which are the keystone of classical mechanics, are three statements that defined the relationships between the forces acting on a body and its motion. They were first disclosed by English physicist and mathematician Isaac Newton.

Newton’s First Law of Motion

Newton’s 1st law states that a body at rest or uniform motion will continue to be at rest or uniform motion until and unless a net external force acts on it.

Newton’s Second Law of Motion

Newton's 2nd law of motion deals with the relation between force and acceleration. According to the second law of motion, the acceleration of an object as built by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.

Newton’s Third Law of Motion

Newton's 3rd law of motion states when a body applies a force on another body that there is an equal and opposite reaction for every action.