Question

A ball is thrown up vertically at a speed of 6.0 m/s. The maximum height reached by the ball (Take \( g = 10 { m/s}^2 \)) is:

• A. 80 m
• B. 100 m
• C. 18 m
• D. 1.8 m
• E. 1 m

Hint:

At maximum height, the velocity of a projectile becomes zero.

Answer 1

The Correct Option is D

The maximum height \( h \) reached by the ball can be calculated using the kinematic equation: \[ v^2 = u^2 - 2gh \] where \( v = 0 \) m/s (final velocity at the top), \( u = 6.0 \) m/s (initial velocity), and \( g = 10 \) m/s\(^2\) (acceleration due to gravity). 
Solving for \( h \), \[ 0 = (6.0)^2 - 2 \times 10 \times h \implies h = \frac{36}{20} = 1.8 { m} \]