A ball falls freely from a height h on a rigid horizontal plane. If the coefficient of resolution is e, then the total distance travelled by the ball before hitting the plane second time is:
he2
h(1+2e2)
h(1-2e2)
h(1+e2)
The correct option is: (B) : h(1+2e2).
Prior to the initial collision, the following relationship exists:
mgh = (1/2)mv₁²
This can be further expressed as:
v₁ = √(2gh)
Following the collision, the velocity becomes v₂. Hence, the relationship can be described as:
v₁/v₂ = e Or, v₂ = ev₁
Considering the subsequent calculation of the ball's reached height:
mgh₂ = (1/2)mv₂²
This leads to the equation:
h₂ = (1/2)e²h
The total distance covered before the second impact is determined by:
h + (1/2)h₂ = h + (1/2)e²h = h(1 + 2e²)
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