Question:
A bag contains 2 red, 3 green and 2 blue balls. 2 balls are to be drawn randomly. What is the probability that the balls drawn contain no blue ball?
A bag contains 2 red, 3 green and 2 blue balls. 2 balls are to be drawn randomly. What is the probability that the balls drawn contain no blue ball?
Updated On: Sep 25, 2024
- \(\frac{5}{7}\)
- \(\frac{10}{21}\)
- \(\frac{2}{7}\)
- \(\frac{11}{21}\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\frac{5}{7}\)
Explanation: Explanation: There are 2 red, 3 green, and 2 blue balls in total. The probability of drawing a blue ball is \(\frac{2}{7}\). Therefore, the probability that the drawn balls contain no blue balls is\( ( 1 - \frac{2}{7} = \frac{5}{7} )\)
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