Question:

A bacterial cell suspension contains $2 x 10^5 $ 𝑐𝑒𝑙𝑙𝑠 π‘šπΏ^{βˆ’1}. The volume of this suspension required to obtain $1.4 x 10^6$ 𝑐𝑒𝑙𝑙𝑠 is ________ π‘šπΏ (rounded off to the nearest integer).

Updated On: Jan 9, 2025
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Correct Answer: 7

Solution and Explanation

The required volume is calculated using the formula:

\( \text{Volume} = \frac{\text{Total cells required}}{\text{Cell concentration per mL}}. \)

Substitute \(1.4 \times 10^6\) cells and \(2 \times 10^5\) cells/mL:

\( \text{Volume} = \frac{1.4 \times 10^6}{2 \times 10^5} = 7 \text{ mL}. \)

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