Step 1: Understanding capacitive reactance.
The capacitive reactance (\( X_C \)) is given by the formula:
\[
X_C = \frac{1}{2 \pi f C}
\]
where \( f \) is the frequency of the source, and \( C \) is the capacitance.
Step 2: Analyzing the change in frequency.
If the frequency is increased from 50 Hz to 200 Hz, the capacitive reactance will decrease because it is inversely proportional to the frequency. Specifically, if the frequency quadruples, the reactance will decrease by a factor of four.
Step 3: Conclusion.
The correct answer is (C) decrease by a factor of four, as the capacitive reactance is inversely proportional to frequency.
Identify the taxa that constitute a paraphyletic group in the given phylogenetic tree.
The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 