We are given:
- Power \( P = 100 \, \text{W} \),
- Voltage \( V = 220 \, \text{V} \).
We can use the formula relating power, voltage, and current:
\[
P = VI
\]
Where:
- \( P \) is the power,
- \( V \) is the voltage,
- \( I \) is the current.
Rearranging the formula to solve for \( I \):
\[
I = \frac{P}{V}
\]
Substituting the given values:
\[
I = \frac{100}{220} = 0.4545 \, \text{A} \approx 0.50 \, \text{A}
\]
Thus, the current flowing through the bulb is \( 0.50 \, \text{A} \).