Understanding the polymerization process:
When AMP molecules polymerize to form poly-(A), they connect through phosphodiester bonds. This condensation reaction releases one water molecule (H₂O, mass = 18) for each bond formed.
Calculating the molecular mass:
Step 1: Total mass of starting material
Starting with 100 AMP units: $$\text{Total mass} = 100 \times 345 = 34,500$$
Step 2: Mass lost during polymerization
To form a 100-nucleotide chain:
Step 3: Consider end groups at physiological pH
At physiological pH, the poly-(A) chain has:
These terminal groups contribute approximately 100 Da to the total mass.
Step 4: Final molecular mass
$$\text{Molecular mass} = 34,500 - 1,782 + 100$$ $$= 32,818 \text{ Da}$$
Answer: 32,818
| List I | List II |
|---|---|
| A. Adenosine | III. Nucleoside |
| B. Adenylic acid | II. Nucleotide |
| C. Adenine | I. Nitrogen base |
| D. Alanine | IV. Amino acid |
Match the LIST I (Enzyme) with LIST II (Catabolic Products)
| LIST-I | LIST-II | ||
|---|---|---|---|
| (Enzyme) | (Catabolic Products) | ||
| A | \(\beta\)-galactosidase | III | Galactose + glucose |
| B | Lecithinase | I | Choline + H$_3$PO$_4$ + fat |
| C | Urease | IV | CO$_2$ + NH$_3$ |
| D | Lipase | II | Glycerol + fatty acids |
Identify the taxa that constitute a paraphyletic group in the given phylogenetic tree.
The vector, shown in the figure, has promoter and RBS sequences in the 300 bp region between the restriction sites for enzymes X and Y. There are no other sites for X and Y in the vector. The promoter is directed towards the Y site. The insert containing only an ORF provides 3 fragments after digestion with both enzymes X and Y. The ORF is cloned in the correct orientation in the vector using the single restriction enzyme Y. The size of the largest fragment of the recombinant plasmid expressing the ORF upon digestion with enzyme X is ........... bp. (answer in integer) 