Question:

A 10 $\mu\text{C}$ charge is placed in an electric field of $ 5 \times 10^3 \text{N/C} $. What is the force experienced by the charge?

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Remember: The force in an electric field depends directly on both the charge and the magnitude of the electric field.
Updated On: Apr 22, 2025
  • \( 5 \times 10^{-2} \, \text{N} \)
  • \( 5 \times 10^{-3} \, \text{N} \)
  • \( 5 \times 10^2 \, \text{N} \)
  • \( 5 \times 10^4 \, \text{N} \)
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The Correct Option is A

Solution and Explanation

Step 1: Use the formula for force in an electric field
The force \( F \) experienced by a charge \( q \) in an electric field \( E \) is given by: \[ F = q E \]
Step 2: Substitute the given values
Given: - Charge \( q = 10 \, \mu\text{C} = 10 \times 10^{-6} \, \text{C} \) - Electric field \( E = 5 \times 10^3 \, \text{N/C} \) \[ F = (10 \times 10^{-6}) \times (5 \times 10^3) = 5 \times 10^{-2} \, \text{N} \]
Answer:
Therefore, the force experienced by the charge is \( 5 \times 10^{-2} \, \text{N} \). So, the correct answer is option (1).
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