Question:

59 g of an amide obtained from a carboxylic acid, RCOOH, upon heating with alkali liberated 17 g of ammonia. The acid is

Updated On: Jun 23, 2023
  • Formic acid
  • Acetic acid
  • Propionic acid
  • Benzoic acid.
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The Correct Option is B

Solution and Explanation

$RCONH_2 + NaOH \rightarrow RCOONa + NH_3$ As 1 mole of NH3 is given by one mole of amide. Thus mol. mass of $RCONH_2$ is A + 12 + 16 + 14 + 2 = 59 or A + 44 = 59 A = 59 - 44 = 15 Hence alkyl group with mol. mass A = 15 is $CH_3$ Thus, acid is $CH_3COOH$ .
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