50 mL of gas A effuses through a pin hole in 146 seconds. The same volume of $CO_2$ under identical condition effuses in 115 seconds. The molar mass of A is
Updated On: Jul 2, 2022
44
35.5
71
None of these
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The Correct Option isC
Solution and Explanation
$\frac{Effusion rate of CO_2}{Effusion rate of A} = \sqrt{\frac{M_A}{M?_{CO_2}}}$$\frac{50/115}{50/145} = \sqrt{\frac{M_A}{44}}$$\frac{M_A}{44} = (1.27)^2$$\therefore \, N_A $ =71