$50.0\, kg$ of $N_{2(g)}$ and $10.0\, kg$ of $H_{2(g)}$ are mixed to produce $NH_{3(g)}$ . Identify the limiting reagent in the production of $NH_3$ in this situation.

The balanced chemical reaction is $ {N2 +3H2<=> 2NH3}$ From the above balanced equation, 1 mol of $N_{2(g)}$ reacts with 3 moles of $H_{2(g)}$ . $\therefore$ Moles of $N_{2}=\frac{50,000\,g}{28\,g\,mol^{-1}}=1785.71\,mol$ or, Moles of $H_{2}=\frac{10,000\,g}{2.106\,g\,mol^{-1}}=4960.3\,mol$ $\therefore 1785.7\, mol$ of $N_2$ react with $3 ? 1785.7\, mol = 5357.1\, mol$ but we have $4960.3 \,mol$ of $H_2$ only. Therefore, $H_2$ is a limiting reagent.

$50.0\, kg$ of $N_{2(g)}$ and $10.0\, kg$ of $H

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Some Basic Concepts of Chemistry

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Chemistry plays an important role in understanding various subjects like physics, geology and biology.
Chemistry is a core branch of science that explains us about the various compositional properties and interaction of matter. It also helps to understand various chemical reactions.
Chemistry is important in order to understand the behaviour of fertilizers, alkenes, acids, salts, dyes, polymers, drugs, soaps and alloys in organic and inorganic chemistry.
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Classification of Matter

There are two ways of classifying the matter:

(A) Physical Classification:

Matter can exist in three physical states:

Solids - have definite volume and definite shape
Liquids - have definite volume but not definite shape.
Gases - have neither definite volume nor definite shape.

(B) Chemical Classification:

Based upon the composition, matter can be divided into two main types:

Pure Substances are defined as a single substance (or matter) which cannot be separated by simple physical methods. Pure substances can be further classified as (i) Elements (ii) Compounds
Mixtures are the combination of two or more elements or compounds which are not chemically combined together and may also be present in any proportion.

$50.0\, kg$ of $N_{2(g)}$ and $10.0\, kg$ of $H_{2(g)}$ are mixed to produce $NH_{3(g)}$. Identify the limiting reagent in the production of $NH_3$ in this situation.

The Correct Option is B

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