Question:
\(\sqrt{3}x + \sqrt{2}y = 2\sqrt{2}\) ; \(\sqrt{2}x - \sqrt{3}y = 3\sqrt{3}\) implies \(x=,y=\)
\(\sqrt{3}x + \sqrt{2}y = 2\sqrt{2}\) ; \(\sqrt{2}x - \sqrt{3}y = 3\sqrt{3}\) implies \(x=,y=\)
Updated On: May 17, 2024
- 1,2
- \(\sqrt{6},-1\)
- 2,1
- \(\sqrt{2},\sqrt{3}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\sqrt{6},-1\)
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